3m^2-41m=-60

Solution for 3m^2-41m=-60 equation:

3m^2-41m=-60

We move all terms to the left:

3m^2-41m-(-60)=0

We add all the numbers together, and all the variables

3m^2-41m+60=0

a = 3; b = -41; c = +60;
Δ = b2-4ac
Δ = -412-4·3·60
Δ = 961
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{961}=31$
$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-41)-31}{2*3}=\frac{10}{6}
=1+2/3
$
$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-41)+31}{2*3}=\frac{72}{6}
=12
$